Why are you breaking the integral at x= 0? At x= 0, |x+ 1|= |1|= 1 and there is no problem. |a| changes "formula" when a= 0 so |x+ 1| changes when x+ 1= 0 or x= -1. Break the integral into .
I am having trouble understanding the following definite integral:
The way I did it is as follows:
from which I got a similar answer to the correct one which looked as follows:
My question is that due to it being an absolute value surely you have to break the integral up into ?