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Math Help - Differential Equations

  1. #1
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    Smile Differential Equations

    I think I'm understanding better, but still not quite there yet. Please point out my mistakes (if any lol).

    Find the general solution of the given differential:

    dy/dt = [te^y]/(2t-1)

    d/e^y (te^y) = d/dt 2t-1

    integral d/e^y (te^y) d/dy = integral d/dy (2t-1) d/dt

    integral e-y = 2 integral (t-1) dt
    ln -[y] = 2/(t-1) + C
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  2. #2
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    Quote Originally Posted by startingover View Post
    I think I'm understanding better, but still not quite there yet. Please point out my mistakes (if any lol).

    Find the general solution of the given differential:

    dy/dt = [te^y]/(2t-1)

    d/e^y (te^y) = d/dt 2t-1

    integral d/e^y (te^y) d/dy = integral d/dy (2t-1) d/dt

    integral e-y = 2 integral (t-1) dt
    ln -[y] = 2/(t-1) + C
    The mistake is that you are dividing both sides by te^{y} you shoudl inside divide by e^y.

    So you end up with,
    e^y \cdot \frac{dy}{dx} = \frac{t}{2t-1}
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  3. #3
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    here is the solution

    Here is the solution
    Attached Thumbnails Attached Thumbnails Differential Equations-18june2007.gif  
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