# Quick question about two-path limit test

• Oct 13th 2010, 09:17 PM
downthesun01
Quick question about two-path limit test
How do you decide what two paths to take? For example:

$\frac{x^{2}y}{x^{4}+y^{2}}$

Can I pick any paths I want? For example:

The line $x=0$

$lim_{x\rightarrow 0}$ $\frac{0}{y^{2}}=0$

And the line $y=x^{2}$

$lim_{y\rightarrow x^{2}}$ $\frac{x^{2}*x^{2}}{x^{4}+x^{4}}=\frac{1}{2}$
• Oct 14th 2010, 12:48 AM
Prove It
What point are you making this function tend to?
• Oct 14th 2010, 12:50 AM
downthesun01
Sorry. (0,0)
• Oct 14th 2010, 01:00 AM
Prove It
Quote:

Originally Posted by downthesun01
How do you decide what two paths to take? For example:

$\frac{x^{2}y}{x^{4}+y^{2}}$

Can I pick any paths I want? For example:

The line $x=0$

$lim_{x\rightarrow 0}$ $\frac{0}{y^{2}}=0$

And the line $y=x^{2}$

$lim_{y\rightarrow x^{2}}$ $\frac{x^{2}*x^{2}}{x^{4}+x^{4}}=\frac{1}{2}$

This is probably easiest to solve by converting to polars, remembering that $x = r\cos{\theta}, y = r\sin{\theta}, x^2+y^2=r^2$...

$\displaystyle{\lim_{(x,y) \to (0,0)}\frac{x^2y}{x^4 + y^2} = \lim_{r \to 0}\frac{r^2\cos^2{\theta}\cdot r\sin{\theta}}{r^4\cos^4{\theta} + r^2\sin^2{\theta}}}$

$\displaystyle{= \lim_{r \to 0}\frac{r^3\cos^2{\theta}\sin{\theta}}{r^2(r^2\cos ^4{\theta} + \sin^2{\theta})}}$

$\displaystyle{= \lim_{r\to 0}\frac{r\cos^2{\theta}\sin{\theta}}{r^2\cos^4{\th eta} + \sin^2{\theta}}}$

$\displaystyle{= \frac{0}{\sin^2{\theta}}}$.

Since this value could change when $\sin^2{\theta} = 0$, we can say that the limit does not exist.
• Oct 14th 2010, 01:14 AM
downthesun01
Thanks but we haven't learned about polars yet. If someone could explain it for me by using the two-path method, I would much appreciate it. Thanks
• Oct 14th 2010, 04:12 AM
HallsofIvy
The original question was "how do you decide which two paths to take". The answer is, you don't. You try different paths, perhaps many, until you find two which give different limits. If there exist different paths that give different limits, then the limit itself does not exist.

The problem with that is that you can't try all paths and there is no way of knowing in advance which, if any, paths will give different limits. Even if you tried all straight lines, by using "y= mx" with m left variable, and found that you got the same limit for all straight line paths, that is not enough. There are functions which give the same limit for all straight paths but different limits for curved paths and so do NOT have a "limit".

If, for some paths, you get different limits then you know that the limit itself does not exist. If, however, you get the same limit for every path you try, you still do NOT know whether or not the limit itself exists.