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Math Help - integral (partial fraction)

  1. #1
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    integral (partial fraction)

    find  \int \frac{4 x^2 + 10 x + 24}{(x - 5)(x^2+4)} dx

     \frac{4 x^2 + 10 x + 24}{(x - 5)(x^2+4)} = \frac{A}{x - 5} + \frac{B x + C}{x^2+4}

    4x^2+10x+24 = A(x^2+4)+(Bx+C)(x-5)

    I was able to find A by:  170 = A(29), A= 6
    need help finding B and C
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  2. #2
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    Re:

    RE:

    Part #1
    Attached Thumbnails Attached Thumbnails integral (partial fraction)-38-part-1.jpg  
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  3. #3
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    Re:

    RE:

    Part #2
    Attached Thumbnails Attached Thumbnails integral (partial fraction)-38-part-2.gif  
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  4. #4
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    thank you very much qbkr21
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