1. ## integral (partial fraction)

find $\int \frac{4 x^2 + 10 x + 24}{(x - 5)(x^2+4)} dx$

$\frac{4 x^2 + 10 x + 24}{(x - 5)(x^2+4)} = \frac{A}{x - 5} + \frac{B x + C}{x^2+4}$

$4x^2+10x+24 = A(x^2+4)+(Bx+C)(x-5)$

I was able to find A by: $170 = A(29), A= 6$
need help finding B and C

RE:

Part #1

3. ## Re:

RE:

Part #2

4. thank you very much qbkr21