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Math Help - having trouble with setting up integral by parts

  1. #1
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    having trouble with setting up integral by parts

    I understand how to solve integrals by parts. My problem lies in setting up the variables so that I can begin solving it.

    Scanned is my work and how I set up the variables in what I believe are good except for the v and dv.

    If I can get v and dv correct then I know how to solve this but need a little kick start.
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  2. #2
    MHF Contributor harish21's Avatar
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    If  dv = sin(2x) dx , then  \displaystyle{v = \frac{-cos(2x)}{2}}
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  3. #3
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    Here is my final answer.
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  4. #4
    MHF Contributor harish21's Avatar
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    \displaystyle{ \int cos(2x) dx = \frac{sin(2x)}{2}}
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  5. #5
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    So we would then multiply 1/2 by [1/2 * sin(2x)] = 1/4 * sin(2x)?
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  6. #6
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    Quote Originally Posted by solidstatemath View Post
    So we would then multiply 1/2 by [1/2 * sin(2x)] = 1/4 * sin(2x)?
    Yes...
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