# Math Help - having trouble with setting up integral by parts

1. ## having trouble with setting up integral by parts

I understand how to solve integrals by parts. My problem lies in setting up the variables so that I can begin solving it.

Scanned is my work and how I set up the variables in what I believe are good except for the v and dv.

If I can get v and dv correct then I know how to solve this but need a little kick start.

2. If $dv = sin(2x) dx$ , then $\displaystyle{v = \frac{-cos(2x)}{2}}$

3. Here is my final answer.

4. $\displaystyle{ \int cos(2x) dx = \frac{sin(2x)}{2}}$

5. So we would then multiply 1/2 by [1/2 * sin(2x)] = 1/4 * sin(2x)?

6. Originally Posted by solidstatemath
So we would then multiply 1/2 by [1/2 * sin(2x)] = 1/4 * sin(2x)?
Yes...