# Math Help - innequality proof

1. ## innequality proof

prof that if a=<b and d=<c is given than |a-c|=<|b-d|
from the sum of the given we get a+d=<b+c
that as far as i went

2. That is not true.
Take $a=1, b = 2, c=2, d=2$

3. If you leave off the magnitude signs, it is true. To prove that statement (without the magnitude signs), you could compare -c with -d.