We normally like to see some work done. Anyway, you are going to need to rewrite the integral like so
and then integrate by parts. Let and then .
See what you can do with that.
With the successive substitutions and the integral becomes...
(1)
Now with a little of patience You can verify that is...
(2)
... and because for is...
(3)
... combining (1), (2) and (3) we arrive to write...
(4)
... where is the 'Riemann Zeta Function'...
Kind regards