1. ## re^itheta

I'm asked to express 4 in the form re^i*theta

Here's what i've done:

r = squreRoot(4^2 + 0^2)
r = 4

How do I find theta?

2. $4 = 4 +0\cdot i$, so $\theta = arctan \left( \frac{0}{4} \right) = arctan(0)$

3. Ok, then 4 written in this form is just simply 4 since 4e^i*0 = 4. RIght?

r = 3, but theta = arctan(3/0)??? 3 divided by 0...

4. Well, $3i$ lies on the positive imaginary axis.

5. Originally Posted by jzellt
I'm asked to express 4 in the form re^i*theta

Here's what i've done:

r = squreRoot(4^2 + 0^2)
r = 4

How do I find theta?
Originally Posted by jzellt
[snip]