So the question is:
Suppose an object moves along a horizontal path with the position function x(t) = 4t – t^2 on the time interval 0 ≤ t ≤ 5, where x is measured in meters and t is measured in seconds. Find the instantaneous velocity of the object from t = 1. Use units to describe what this value means.
I know that the first step is to find the derivative of the position function so:
lim(delta x -> 0) [s(t + delta t) - s(t)] / [delta t]
[((4t + delta t) - t^2) - (4t - t^2)] / [delta t]
Now I don't understand how to simplify this so that I can plug in 1 for t?
I'm sorry if this looks confusing.
Any help is appreciated.