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Math Help - A problem featuring area of a square and rate of change.

  1. #1
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    A problem featuring area of a square and rate of change.

    the length of a rectangle is given by 6t+ 5 and its height is sqrt(t), where t is time in seconds and the dimensions are in centimeters. Find the rate of change with respect to time.

    I am not really quite sure how to do rate of change.. I have read over the examples given for rate of change in the book however, it seems vague and borderline unrelated.. Their problem was dealing with speed and velocity..
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  2. #2
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    Are you finding the rate of change of the area?

    A = (6t+5)\sqrt{t}.


    The rate of change of the area is the derivative of this function.
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    I gave you everything the book gave me to be honest.

    So from here I am guessing I would just use the product rule to find the derivative from what you gave me?
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    The derivative IS the rate of change  dy/dx is the rate of change of y with respect to the change in x... in this case your independent variable is time. so just find  dA/dt


    Yes use the product rule.
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