Hi,
I know this question is easy but I havent done this topic in awhile and I forget how to do it.
I need to sketch the tangent lines to y=f(x) at x=-3 and x=2?
How do I work out the tangent line?
Please
Hi,
I know this question is easy but I havent done this topic in awhile and I forget how to do it.
I need to sketch the tangent lines to y=f(x) at x=-3 and x=2?
How do I work out the tangent line?
Please
I'm getting f(-3) = -0.684. Check your calculations again.
You might want to find the equation of the gradient, by using:
You will get the y intercept of the tangent then.
Then, you connect the y intercept with the point to where the line x = -3 drops vertically on the curve.
I didn't put any apostrophe in my answer, meaning I got f(-3) = -0.684. f'(-3) = -0.279.
You need to find the point on the curve first. You were given x = -3. The y coordinate is given by f(-3).
Now, since you are looking for a tangent at that point, you also need to find f'(3).
Once you get those, you have your coordinates.
f(-3) = -0.684
f'(-3) = -0.279
x = -3
Or, (-3, -0.684) with gradient m = -0.279
Thus, you get the equation of the tangent as being:
This becomes:
Now that you have the equation of the tangent, you can join the points: (-3, -0.684) and (0, -1.521) to get the tangent.