I am having trouble with an integration

The problem is looking for e raised to the integrated function

The answer to the problem states that the result = 1 +.1x

Of course if the .1 was not in the numerator it would be e to the natural log of (1+.1x) divided by e raised to 'ln (1)' and that of course would be (1+.1x) divided by one and we'd have the answer.

When I pull the numerator (.1) outside of the integrand and then integrate I get .1 * (1+.1x), and that is not the stated answer. Help please.