Can someone show me the steps of calculating the limit of the following function?
When x approaches 1 from the left (1 minus), the limit of exp {(4-5x)/(1-x)}.
Thank you very much
Oh, yes... what I was concerning was that since it is 1 - x in the denominator, I cannot directly apply the limit to the fraction.
But thanks Archie! I know how to work it out now! What I need is to take the inverse, (1/x) / (4 - 5x) and evaluate the limit when x approaches 1 from the left and then take the inverse again. That is, the inverse of the limit of the inverse of a fraction is equivalent to the limit of the original function!
I am so happy today! Thanks for letting me know the existence of mathematica!
The fraction is not defined for as this will cause the denominator to be zero.
does not cause a problem for the numerator, however.
As x approaches 1 from below, the fraction is negative, the denominator approaches zero and hence the fraction approaches
As x approaches 1 from above, the fraction is positive, the denominator approaches zero and hence the fraction approaches
doesnt exist since as