Dear MHF experts (btw, you guys rock!! lol),

(someone else's calculations for this, last step is correct, i took the derivative and it equals the original integral)

let sin(θ) = x/5 ; 5 cos(θ) dθ = dx

= 25 ∫ sin²(θ) dθ

= 25/2 ∫dθ - 25/2 ∫cos(2θ) dθ ............. sin²(θ) = (1/2) [1 - cos(2θ)]

= 25/2 θ -25/2 sin(θ)cos(θ) + c

= 25/2 arcsin(x/5) -x/2 √(25 - x²) + c

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I got to the step in bold no problem. I got the first term in the last step right; however, I cannot seem get from the second term in bold to the second term in the last step. I only need help getting from the bold underlined to the last underlined term xD

In the last step that's underlined, I can substitute (x/5)=sinθ ... but cannot figure out what to substitute for cosθ