My problem is:
"Prove that if f is an even function, then f^ is also an even function"
f^ = fourier transform of f."
This is what I've done, after some hints from a teaching assistant:
, since f(x)=f(-x), even function
Choose u=-x ->dx = -du
I can't see how this answers the problem, is there anything wrong in my calculations, or do you have any hints on how to continue? I'm thankful for any help...