I got:

1/2t^(-1/2)(x+14) + SQRT of x.

why is this wrong?

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- Sep 28th 2010, 09:43 PMmelliepDerivative of this function?
I got:

1/2t^(-1/2)(x+14) + SQRT of x.

why is this wrong? - Sep 28th 2010, 09:52 PMProve It
I don't know why your derivative has a $\displaystyle t$ in it.

$\displaystyle y = x^{\frac{1}{2}}(x+14)$.

$\displaystyle \frac{dy}{dx} = x^{\frac{1}{2}}\,\frac{d}{dx}(x + 14) + (x + 14)\,\frac{d}{dx}(x^{\frac{1}{2}})$

$\displaystyle = x^{\frac{1}{2}} + \frac{1}{2}(x + 14)x^{-\frac{1}{2}}$

$\displaystyle = \sqrt{x} + \frac{x + 14}{2\sqrt{x}}$. - Sep 28th 2010, 10:02 PMmelliep
WOWWWWWWW. That was the problem. I inserted a 't' instead of 'x'. I am a smart one obviously.

Thank you.