First of all, v0 cos(12)= 200 ft makes no sense at all. The left hand side of the equation is a speed and the right side is a distance- theycan'tbe equal. Assuming no air resistance, V0cos(12) is the horizontal component of initial velocity and remains so: the horizontal distance traveled is V0cos(12)t. Set that equal to 200 feet and solve for t as a function of V0:

V0cos(12)t= 200 so t= 200/(V0cos(12).

Now, look at the vertical motion. The acceleration due to gravity is -g or about -32.2 feet/sec^2. The vertical speed is V0 sin(12)-32.2 t feet/sec and the vertical height, at time t, is -V0 sin(12)- 16.1t^2. Put your expression for t into that, set it equal to 0 (where the projectile hits the ground again and solve for V0.