$\displaystyle \begin{displaymath}

f(x) = \left\{

\begin{array}{lr}

2-x & if x<-1\\

x & if -1<=x<1\\

(x-1)^2 & if x>=e1

\end{array}

\right.

\end{displaymath} $

I'm supposed to graph this piecewise function and use it to determine the values of a for which the limit of f(x) exists as x approaches a.

I'm not entirely sure how to start this question. Looking on the graph I'm thinking the only place where the limit of f(x) as x approaches a doesn't exist is -1 and 1. Could someone please explain?

That is the graph. So does f(x) exist everywhere 1 and -1