Originally Posted by
startingover OK I am getting really close now...the book shows a negative answer, which I am unsure of.
The velocity v(t) = x'(t) at time t of an object moving along the x axis is given, along with the initial position x(0) of the object.
Find:
the position x(t) at time t
the position of the object at time t=4
the time when the object is at x=3
x'(t) = -2(3t+1)^1/2, x(0) = 4
y=u^1/2
dy = 1/2u^3/2du
x=3t+1
dx = 3dt
x(t) = 1/2 u^3/2 (3t+1)^3/2 dx
x(t) = 4/9(3t+1)^3/2 + C
book says 4/9 should be negative.
Unsure of how to do the position of the object at t=4 and time of x=3. The way I have tried to substitute isn't coming up with the books answer.