Could you explain to uswhyyou did that? I can see that "2.4" and "4.5" are the values for v(t) at times closes to t= 22 but where did "(4- 2)" come from? Well, actually, not -.42 so I guess that was a typo. \frac{2.4- 4.5}{25- 20= \frac{-2.1}{5}= -.42. That looks to me like as good an answer as you can get from this data.

Well, I can see where you got both the numerator and denominator but those are for t= 15 and 20 and don't give any information about t= 22.Then I did (4.5-7)/(20-15) and got -.5.

I must confess that why you areI added -.42 and -.5 and got -.92 and divided that by 2 and my answer was: -.46 which makes no sense..?doingmakes no sense. Why would you add those results and divide by 2?

The time given, t= 22, is not on the table but lies between t= 20 and t= 25. The average rate of change of v between those is

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