there k=6 (not 36 !)
What k is in this case?
Or you want this
Please find k in this case.
So I have two questions where I cannot find apply the antiderivative rule properly.
g(x) = 1/ 9(x^2 + 1)
The rule is 1 / (1+k^2 * x^2) = 1/k * tan^-1 * kx + C
I get 1/9 * tan^-1 * 9x + C
The answer for somereaso does not have a 9 in front of the x for the tan. How come? Isn't the K = 9 ?
Same problem except the question is 1 / 1+ 36x^2 and I get 1/36 * tan^-1 36x + C
K should be 3 in that case.
Apparently I've been using k in a form where it's squared but I cannot see that at first glance. I mean, I know 36 is the 6^2 but say for example it was 41 instead of 36. Is there a reason why when the number can be square rooted we take that instead of the number given?