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Math Help - Help evaluating Indefinite Integral (Calc. 1)

  1. #1
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    Help evaluating Indefinite Integral (Calc. 1)

    I understand that I have to use u-substitution on one of the terms but I don't see which one.

    I really have tried to solve this. I'm self-studying and hence have no real other recourse. I have searched the forum/google for similar problems but to no avail. Thanks and hello.

    \int\frac{x\sin\sqrt{2x^2-5}}{\sqrt{2x^2-5}}dx
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by nnnnnnnnnnnnnnnnnn View Post
    I understand that I have to use u-substitution on one of the terms but I don't see which one.

    I really have tried to solve this. I'm self-studying and hence have no real other recourse. I have searched the forum/google for similar problems but to no avail. Thanks and hello.

    \int\frac{x\sin\sqrt{2x^2-5}}{\sqrt{2x^2-5}}dx
    Here it is useful to be able to spot that you have a function of the form:

    \displaystyle \frac{d}{dx}g(f(x))=f'(x)g'(f(x)), so:

    consider the derivative of \cos(\sqrt{2x^2-5})

    CB
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  3. #3
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    I see it now. Thanks, CaptainBlack!
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