Help evaluating Indefinite Integral (Calc. 1)

**nnnnnnnnnnnnnnnnnn** · September 25th 2010, 10:29 AM

I understand that I have to use u-substitution on one of the terms but I don't see which one.

I really have tried to solve this. I'm self-studying and hence have no real other recourse. I have searched the forum/google for similar problems but to no avail. Thanks and hello.

$\int\frac{x\sin\sqrt{2x^2-5}}{\sqrt{2x^2-5}}dx$

**CaptainBlack** · September 25th 2010, 11:18 AM

Originally Posted by nnnnnnnnnnnnnnnnnn

I understand that I have to use u-substitution on one of the terms but I don't see which one.

I really have tried to solve this. I'm self-studying and hence have no real other recourse. I have searched the forum/google for similar problems but to no avail. Thanks and hello.

$\int\frac{x\sin\sqrt{2x^2-5}}{\sqrt{2x^2-5}}dx$

Here it is useful to be able to spot that you have a function of the form:

$\displaystyle \frac{d}{dx}g(f(x))=f'(x)g'(f(x))$ , so:

consider the derivative of $\cos(\sqrt{2x^2-5})$

CB

**nnnnnnnnnnnnnnnnnn** · September 25th 2010, 11:39 AM

I see it now. Thanks, CaptainBlack!

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