(intetral sign) 1/ (1+ 2^(1/2)) dx
I subsituted u= 1 + 2^(1/2) but got no where after du = x^(-1/2) dx
Algebraic help or hints please.
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is a constant. What does that tell you about its antiderivative?
Maybe have a closer look at your quesiton as,
I am so sorry that I incorrectly posted the problem. I should of taken the time to double check instead of wasting your time.
The question is ∫ 1/ (1 + √(2x) )
Again I substituted 1 + √(2x) and got stuck with du = 1/√(x)
Now let so that so that .
Now long divide to get .
Shorter way: let , then .
We have then . But from , we get .
So we have
As , this is .
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