once the integral is found for dy/dx=y^2+1, how do you find the equation that satisfies the initial condition of y(4)=0? i put y=tan(x+4), but it's wrong.
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Originally Posted by sw3etazngyrl once the integral is found for dy/dx=y^2+1, how do you find the equation that satisfies the initial condition of y(4)=0? i put y=tan(x+4), but it's wrong. i got y = tan(x - 4). what was the answer?
i don't know, it doesn't tell me. it only tells me that my answer is wrong.
how did you get that answer?
Originally Posted by sw3etazngyrl i don't know, it doesn't tell me. it only tells me that my answer is wrong. oh. you're inputing answers into some online application? is y = tan(x - 4) also wrong? we have Now Thus our solution is
the answer you got is right. thanks! but how did you arrive at that?
It's just arctan formula.
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