I'm a little rusty with my partial fractions so I just need a refresher.

The equation is $\displaystyle 1/(x+1)(x+2)(x+4)$ I have

$\displaystyle A/x+1 + B/x+2 + C/x+4$

Then common denominators

$\displaystyle (x+1)(x+2)(x+4)= A(x+2)(x+4) + B(x+1)(x+4) + C(x+1)(x+2)$

After this can I do where, x=-2 for example? Cause then I will get 0=-2B

And then keep plugging in values for x? Or is there another way which I complete forgot about