I have a series from n=1 to infinity of n/(4^n). Can this convert into a geometric series? and so how?
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Originally Posted by guyonfire89 I have a series from n=1 to infinity of n/(4^n). Can this convert into a geometric series? and so how? Yes it can by differentiation. Start with . Differentiate to show Then let
Last edited by Plato; Sep 20th 2010 at 03:59 PM.
Can someone explain how x=1/4?
Originally Posted by guyonfire89 Can someone explain how x=1/4? You let and the LHS, that's the sum becomes which is your original sum. Do the same, i.e. let for the RHS, that's and you will find what it evaluates to.
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