Suppose that f(5) = -1, f'(5) = 2, g(5) = 5, g'(5)=-3 find (g/(f^2+g))' (5). I must be doing something wrong. Because my answer is way off. Or maybe it's because I'm not understanding the notation properly.
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Originally Posted by pewpew01 Suppose that f(5) = -1, f'(5) = 2, g(5) = 5, g'(5)=-3 find (g/(f^2+g))' (5). I must be doing something wrong. Because my answer is way off. Or maybe it's because I'm not understanding the notation properly. quotient rule and chain rule, correct? $\displaystyle \displaystyle \left(\frac{g}{f^2+g}\right)' = \frac{(f^2+g) \cdot g' - g(2f \cdot f' + g')}{(f^2+g)^2}$ now sub in your given values and determine the derivative at 5
Oh... right. Chain rule and quotient. How could I forget about it. kk thanks.