I agree with everything up until this point:
v^2=2^2+1^2.
I think you meant to write
v^2=4^2+2^2, right?
Hi, just wondering if I got this one right.
A circle is given by an equation (see image). The first task is to find y' and y'' in the point (0,0). This I have done. Using implicit differentiation I got:
y'=2 and y''=-5
Now, the second question reads:
"The circle describes the path of a particle. In the point (0,0) its speed in the x-direction, dx/dt, is 2 m/s. Find the particle's speed in the y-direction and the total speed."
My reasoning goes like this:
Since y' in the point (0,0) is 2, the particle's speed in the y-direction is double that in the x-direction. Therefore it must be 4 m/s.
The total speed (v) is the sum of the two vectors x and y, and can be found using Pythagoras:
v^2=2^2+1^2
v=√5
Does this make sense to you, or am I way off?
Thanks