Thread: limits

i have the function h(x) = -1/(1-e^(1/x)) the question is asking what is the limit of h(x) = ? as x-->0, my answer is dne. the graph has a break at x=0 so that limit does not exist. im wondering if i worded that right or if my thinking on this problem is correct? any help would be appreciated...

Originally Posted by slapmaxwell1

i have the function h(x) = -1/(1-e^(1/x)) the question is asking what is the limit of h(x) = ? as x-->0, my answer is dne. the graph has a break at x=0 so that limit does not exist. im wondering if i worded that right or if my thinking on this problem is correct? any help would be appreciated...

Your question makes more sense if x approaches zero from above zero,
or if x approaches zero from below zero.

Then you can evaluate two limits, but yes, there is a jump discontinuity at x=0.