A car is traveling C meters behind a truck, both traveling at a constant speed of V m/s. The road widens L meters ahead of the truck and there is an overtaking lane. The car accelerates at a uniform rate so that it is exactly alongside the truck at the beginning of the overtaking lane.

a)What is the acceleration of the car?

b) Show that the speed of the car as it passes the truck is V(1+ 2C/L)

Have tried part a), but gotten (V^2C)/(L^2) instead it should be (2V^2C)/(L^2)

Any thoughts?

This question is in my book as Rates of Change, but i am not sure as my approach was non - calculus based.