not quite sure how to do this one: $\displaystyle \int^2_1 e^{lnu}\frac{1}{u}du $
Follow Math Help Forum on Facebook and Google+
Originally Posted by viet not quite sure how to do this one: $\displaystyle \int^2_1 e^{lnu}\frac{1}{u}du $ substitution. let t = ln(u)
Note, $\displaystyle e^{\ln u}=u$ So, $\displaystyle e^{\ln u}\cdot \frac{1}{u} = \frac{u}{u}=1$
Originally Posted by ThePerfectHacker Note, $\displaystyle e^{\ln u}=u$ So, $\displaystyle e^{\ln u}\cdot \frac{1}{u} = \frac{u}{u}=1$ yeah, i missed that. thanks
View Tag Cloud