let f(x) = 1/x for x>0. If E is any positive quantity (i.e. E >0), find a positive number S (i.e. S>0) which is such that :

if 0<|x-3|<S, then |f(x) - 1/3| < E

Note: E - epsylon, and S - delta

Am not sure of how to start. Any help would be appreciated.