Maximum and minimum value of the function f(x)=1/2x^3-x^2

on the interval: -1 ≤x ≤1

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- Sep 16th 2010, 06:45 PMdvmasakaFunctions
Maximum and minimum value of the function f(x)=1/2x^3-x^2

on the interval: -1 ≤x ≤1 - Sep 16th 2010, 07:06 PMacevipa
What function are you talking about?

$\displaystyle f(x)=\frac{1}{2x^3-x^2}$ or $\displaystyle f(x)=\frac{1}{2x^3}-x^2$ - Sep 16th 2010, 09:47 PMdvmasaka
I am talking about the function

0.5 of x^3 - x^2 - Sep 16th 2010, 09:57 PMpickslides
- Sep 17th 2010, 01:11 AMHallsofIvy
I am going to assume you mean (1/2)x^3- x^2 just because it is simplest. Your notation is still ambiguous.

Now, what have you learned about this? Do you know this theorem: "A function takes on it maximum and minimum values on an interval in one these places:

1) at the endpoints of the interval

2) where the derivative does not exist

3) where the derivative is 0.

If I have the right function, it is a polynomial and its derivative always exists. Can you find the derivative?