Determine the equation of the tangent to the curve f(x)=x*sqrt(1-x^2) at x=1/2 ???
What I have done:
y=sqrt3/4
((1/2),(sqrt3/4))
I am having problem finding the derivative f'(1/2). I know that f'(1/2) = 1/sqrt3
Can anyone help me by showing me how they have done f'(1/2) step by step