Find the coordinates where the gradient of the tangent to y = 2x^2 - 5x + 2:

a) is parallel to the line 1 - 3x.

b) equal to the gradient of the function g(x) = 1/3x^3 - x^2 for the same value(s) of x.

I've been trying to figure it out by doing 1 - 3x = dy/dx but I can't get what the answer says and as for b, I just don't get it at all..

Please help and show working! Thanks a lot.