lets see if I am understanding this any better: integral (2e^u)+(6/u)+(ln2)dx = e^2u + 6(lnu) + 1/2 + C
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Originally Posted by becky lets see if I am understanding this any better: integral (2e^u)+(6/u)+(ln2)dx = e^2u + 6(lnu) + 1/2 + C Thus, the total sum is the answer.
Last edited by ThePerfectHacker; June 4th 2007 at 07:17 PM.
how come 2e^u isn't supposed to be e^2u or e^2^u?
Originally Posted by becky how come 2e^u isn't supposed to be e^2u or e^2^u? Because if it were then the derivative would be . Which is wrong.
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