# Math Help - integrals

1. ## integrals

lets see if I am understanding this any better:

integral (2e^u)+(6/u)+(ln2)dx
= e^2u + 6(lnu) + 1/2 + C

2. Originally Posted by becky
lets see if I am understanding this any better:

integral (2e^u)+(6/u)+(ln2)dx
= e^2u + 6(lnu) + 1/2 + C
$\int 2e^x + \frac{6}{x} + \ln 2 dx = \int 2e^x dx + \int \frac{6}{x} dx + \int \ln 2 dx$

$\int 2e^x = 2e^x +C$

$\int \frac{6}{x} dx = 6\ln |x|+C$

$\int \ln 2 dx = x\ln 2 +C$

Thus, the total sum is the answer.

3. ## unsure of 2e^u

how come 2e^u isn't supposed to be e^2u or e^2^u?

4. Originally Posted by becky
how come 2e^u isn't supposed to be e^2u or e^2^u?
Because if it were $e^{2u}$ then the derivative would be $2e^{2u}$. Which is wrong.