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Math Help - integrals

  1. #1
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    Post integrals

    lets see if I am understanding this any better:

    integral (2e^u)+(6/u)+(ln2)dx
    = e^2u + 6(lnu) + 1/2 + C
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  2. #2
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    Quote Originally Posted by becky View Post
    lets see if I am understanding this any better:

    integral (2e^u)+(6/u)+(ln2)dx
    = e^2u + 6(lnu) + 1/2 + C
    \int 2e^x + \frac{6}{x} + \ln 2 dx = \int 2e^x dx + \int \frac{6}{x} dx + \int \ln 2 dx

    \int 2e^x = 2e^x +C

    \int \frac{6}{x} dx = 6\ln |x|+C

    \int \ln 2 dx = x\ln 2 +C

    Thus, the total sum is the answer.
    Last edited by ThePerfectHacker; June 4th 2007 at 08:17 PM.
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  3. #3
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    unsure of 2e^u

    how come 2e^u isn't supposed to be e^2u or e^2^u?
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  4. #4
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    Quote Originally Posted by becky View Post
    how come 2e^u isn't supposed to be e^2u or e^2^u?
    Because if it were e^{2u} then the derivative would be 2e^{2u}. Which is wrong.
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