Hello, Becky!
You're expected to know that: .
We have: .
. .
. .
We have: .
. .
. .
I am having a hard time understanding this...you all do a much better job of explaining things than my textbook...hopefully between both, I can get a better understanding...
Integral (3square root y) - (2/y^3) + (1/y) dy
=3y^1/2 - 2y^-3 + y^-1 dy
=3(y3/2dy) - 2(y^-2dy) + y^0) dy
=2y^3/2 = 1/y^2 + y + C
and on this one I am even more lost:
integral (1/2y - 2/y^2 + 3/square root y)
= 2y^-1 - 2y^-2 + 3y^-1/2 dy