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Math Help - Evaluate

  1. #1
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    Evaluate

    Evaluate  \int^{\frac{\pi}{2}}_{0}2cosx+3sin2xdx + |\int^{\frac{5\pi}{6}}_{\frac{\pi}{2}}2cosx+3sin2x  dx|

    The ans to this question is 4.25units^2 which is different from my answer of 8.25units^2

    What I did

     \int^{\frac{\pi}{2}}_{0}2cosx+3sin2xdx + |\int^{\frac{5\pi}{6}}_{\frac{\pi}{2}}2cosx+3sin2x  dx| = [2sinx-\frac{3}{2}cos2x]^{\frac{\pi}{2}}_{0}+|[2sinx-\frac{3}{2}cos2x]^{\frac{5\pi}{6}}_{\frac{\pi}{2}}|
    =(3.5-(-1.5))+|(0.25-3.5)|
    =8.25units^2
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  2. #2
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    That's correct.
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  3. #3
    Senior Member Educated's Avatar
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    Maybe you got it right and the answer of 4.25 is wrong.

    I got the answer of 8.25 as well.
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