f(x) = e^-x^2
f'(x) = e^-x^2 + (-2x)
f'(x) = -2xe^-x^2
f"(x) = -2x3^-x^2 +e^-x^2 + (-2x)
f"(x) =-4x(2e^-x^2)
how do you solve these types (e^-x^2) of problems to find the inflection point and concavity?
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f(x) = e^-x^2
f'(x) = e^-x^2 + (-2x)
f'(x) = -2xe^-x^2
f"(x) = -2x3^-x^2 +e^-x^2 + (-2x)
f"(x) =-4x(2e^-x^2)
how do you solve these types (e^-x^2) of problems to find the inflection point and concavity?
Hello,Quote:
Originally Posted by confusedagain
I'm not quite certain if I read your problem correctly...
. Use chain rule to get the first derivation:
f'(x) = 0 if x = 0
Use product rule to get the second derivation:
f''(x) = 0 if 4x² - 2 = 0 that means
the figure show the inflection points
umm...there's no figureQuote:
Originally Posted by curvature