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Thread: Finding area of 3D triangle

  1. #1
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    Finding area of 3D triangle

    As you've probably guessed, I've started multi-variable calculus. I'm struggling a bit to wrap my head around it.


    I'm sure this is an easy question, but I don't know where to begin.

    Find the area of the triangle with vertices at A(1,1,1), B(2,3,4), C(5,2,6)

    Any help is appreciated.
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  2. #2
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    Quote Originally Posted by maxreality View Post
    Find the area of the triangle with vertices at A(1,1,1), B(2,3,4), C(5,2,6).
    Hint: The area is equal to \tfrac12AB\cdot AC\cdot\sin A, which is half the length of the cross product vector \vec{AB}\times\vec{AC}.
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  3. #3
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    Got it! Terribly easy once I worked through it. I think I'm trying to visualize and look to deep when the answer isn't as complicated as I'm making it.

    Thanks!
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