If y = (x^2 + 3x)cosx , find the value of dy/dx when x=0 Can someone show me how to do this q please. Thanks
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Originally Posted by Detanon If y = (x^2 + 3x)cosx , find the value of dy/dx when x=0 Can someone show me how to do this q please. Thanks Quotient Rule? You'd be much better off with the Product Rule since we're not doing any division here. The product rule is In your case and Once you've differentiated find . For reference I get an answer of 3
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