Could someone verify if I did this right.

http://img73.imageshack.us/img73/2226/54677980ld2.png

f’(x)= -3x^2+6x+9

f’’(x)= -6x+6

0= -6(x-1)

x=1

f’(1)=12

therefore the max slope is 12

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- June 2nd 2007, 07:29 AMSportfreundeKeaneKentMax Slope of Curve
Could someone verify if I did this right.

http://img73.imageshack.us/img73/2226/54677980ld2.png

f’(x)= -3x^2+6x+9

f’’(x)= -6x+6

0= -6(x-1)

x=1

f’(1)=12

therefore the max slope is 12 - June 2nd 2007, 07:51 AMCaptainBlack
You have not justified the claim that this is a maximum, you have just

found a stationary point for the slope.

If f'''(1)<0, then this point will be a maximum for the slope

f'''(1)<0 then it is a minimum

f'''(1)=0 it is indeterminate and further work will be needed.

RonL - June 2nd 2007, 08:24 AMcurvaturethe largest slope
the maximum slope