Prove that $\displaystyle \[ \sin 1 >\frac{1}{\sqrt[4]{2}} \] $
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find both sides: $\displaystyle \sin 1 = 0.84147$ $\displaystyle \frac{1}{\sqrt[4]{2}} = 0.84089$
Originally Posted by pankaj Prove that $\displaystyle \[ \sin 1 >\frac{1}{\sqrt[4]{2}} \] $ How did you do this eventually?
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