Can anyone demonstrate the difference quotient f(x) = -6/sqrt(3-4x)
I have worked on that problem for an hour.. tried a few different things.. and I'm flat out lost...
i have gotten so far as -6(sqrt(3-4x-4h) + 6(sqrt(3-4x) / h(sqrt(3-4x))(sqrt(3-4x-4h) however, from there I become unsure what to do. I've thought about multiplying the sqrt on the bottom to give (h)(3+4x)(sqrt(-4h) then multiplying top and bottom by (sqrt(-4h) however, for some reason it seems like doing that is just going to end up leading me in circles.. I thought about multiplying the top using the difference of squares.. but, then that complicates the bottom even more..
If that is what I have to do I will do it.. but, it seems unrealistic to go that route because, I would think I would ultimately complicate the top again clearing the bottom..