1. ## intergration

Hei.

This is the issue:

Intergrate and derivate v(t)=0,5Bt^2 (B=beta).

2. $\displaystyle v' = .5(2)\beta t$

$\displaystyle \int v \cdot dt = \frac{.5}{3} \beta t^3 + c$

3. Originally Posted by ThomasWes
Hei.

This is the issue:

Intergrate and derivate v(t)=0,5Bt^2 (B=beta).

So we should do them for you? Is $\beta$ a constant? If so then the problem is really just finding the integral and derivative of $t^2$. Isn't that one of first things you learn in Calculus?