I have to find the integral of (x^2)(arccothx) dx
I have used integration by parts with
u = arccothx
du = 1/(1-x^2)
dv = x^2
v = 1/3*x^3
which i get:
(1/3)(x^3 * arccothx) - integral (x^3)/3(1-x^2)
i am stuck here as I do not know if I have to use polynomial long division on the integrand above or what the next step might be.