I have to find the integral of (x^2)(arccothx) dx

I have used integration by parts with

u = arccothx

du = 1/(1-x^2)

dv = x^2

v = 1/3*x^3

which i get:

(1/3)(x^3 * arccothx) - integral (x^3)/3(1-x^2)

i am stuck here as I do not know if I have to use polynomial long division on the integrand above or what the next step might be.