I am having difficulty finding the area between these two curves:

$\displaystyle

r = \sin{2\Theta}$ and $\displaystyle r = \cos{2\Theta}$

I setup the integral like this:

$\displaystyle

\int_{0}^{\pi^/8}1/2(\cos{2\Theta}^2 - \sin{2\Theta}^2) d\Theta

$

I multiply the answer of the integral by 16 for the 16 parts of the graph but I cannot arrive at the right answer.

Any help is appreciated of where I am going wrong.

Thanks