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Math Help - Equation of Tangent

  1. #1
    kye20
    Guest

    Equation of Tangent

    Hey,
    Have Maths test tomorrow and having abit of trouble with this question:
    Find equation of tangent to the curve:
    2x^2+3x+4 at point (-2,6)
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  2. #2
    Newbie
    Joined
    May 2007
    Posts
    6
    first take the derivative of the function which is
    4x+3, the derivative function tells you the slope at any point of the original function. you plug -2 into the derivative function to find the slope at the point. The slope is -5 . after that you us y=mx+b(where m is the slope) form to solve for your tangent line. you then plug in your slope and your given point (-2,6) into the question and solve for b. so you will end up with 6=-5(-2)+b when you solve for b you get -4. so your tangent line equation is y=-5x -4
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