I'm having trouble integrating this function:
$\displaystyle \int \sqrt{2-2\cos{4t}} dt$
So far I've tried substitution and that didn't work out so well. Please help!
Ok, I've used the trig identities to change the integral to this:
$\displaystyle \int \sqrt{4 \sin^2{2t}}dt$
I think what is throwing me off is the fact that this function is under the radial. At this point, would substitution work if I use $\displaystyle u= \sin^2{2t}$? Is this the correct integration method to use?