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Math Help - Surface integral over an annulus

  1. #16
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    Ackbeet, while we're on this subject

    What can you tell me about Diamond Transforms?
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  2. #17
    A Plied Mathematician
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    What can you tell me about Diamond Transforms?
    Absolutely nothing. I've never heard of them before. Are they known as something else? Here's a list of transforms. I don't see diamond transforms on there at all. Could you describe them a bit?
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  3. #18
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    Quote Originally Posted by Ackbeet View Post
    Absolutely nothing. I've never heard of them before. Are they known as something else? Here's a list of transforms. I don't see diamond transforms on there at all. Could you describe them a bit?
    Unfortunately when I did a Google search, nothing relevant turned up and this term was used by a poster on a prior thread so I'll consider the matter closed.
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  4. #19
    Senior Member AllanCuz's Avatar
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    Quote Originally Posted by wonderboy1953 View Post
    Since you were never one for numbers, what brings you to a math website?

    Since this is the second time (besides this thread) that I haven't gotten an answer to my question leads me to believe that no such formula exists to transform a double integral into a single integral. Can you prove me wrong?
    I'm here for the entertainment. Clearly!

    Perhaps I didn't use the term "transform" in a strict mathematical sense. I was more refering to the fact that as you compute a multiple integral, it reduces to a single integral, which reduces to some expression.

    For example,

    If we want the area between  y=x^2 and  y=x from 0 to 1 we can either express it as,

     \int_a^b [ F(x) - G(x) ] dx \to \int_0^1 (x-x^2) dx

    or

     \int_0^1 dx \int_{x^2}^x dy

    Clearly the second reduces to the first representation. It's not a "transformation" persay.
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